document.write( "Question 658567: Please help!!!!!\r
\n" ); document.write( "\n" ); document.write( "Find the surface area of the cylinder. Round to nearest tenth.\r
\n" ); document.write( "\n" ); document.write( "Picture of the problem > http://i49.tinypic.com/314pmae.png
\n" ); document.write( "thanks in advance!!\r
\n" ); document.write( "\n" ); document.write( "the answer is not 39.3in cubed\r
\n" ); document.write( "\n" ); document.write( "please explain how you came to that answer also, please. \n" ); document.write( "

Algebra.Com's Answer #410333 by kevwill(135) $\"\"$ $\"About$

You can put this solution on YOUR website!
You're probably forgetting the surface area of the two circles at the ends of the cylinder.\r
\n" ); document.write( "\n" ); document.write( "d = 2.5 in., h = 5 in.\r
\n" ); document.write( "\n" ); document.write( "Area of both circles = $\"2%2Api%2A%28d%2F2%29%5E2\"$ = 9.8 square inches
\n" ); document.write( "Area of the tube = $\"pi%2Ad%2Ah\"$ = 39.3 square inches
\n" ); document.write( "Total surface area = 49.1 square inches\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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