document.write( "Question 657689: Two planes make a 1000 mile flight, one flying 75 miles per hour faster than the other. The quicker plane makes the trip 3 hours faster. How long did it take the slower plane to complete the flight? \n" ); document.write( "
Algebra.Com's Answer #410331 by kevwill(135)![]() ![]() You can put this solution on YOUR website! Let s be the speed of the slower plane and s+75 be the speed of the faster plane. \r \n" ); document.write( "\n" ); document.write( "The time it takes the slower plane to make the flight is \n" ); document.write( "The time it takes the faster plane to make the flight is \n" ); document.write( "\n" ); document.write( "The difference in these two times is 3 hours, so \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We can solve for s using the quadratic equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So s = -200 or s = 125. We'll ignore the negative answer because the planes are not flying backward. \n" ); document.write( "So the slower plane is flying at 125 mph and completes the trip in 8 hours. \n" ); document.write( "The faster plane is flying at 200 mph and completes the trip in 5 hours. \n" ); document.write( " \n" ); document.write( " |