document.write( "Question 658520: find three consecutive odd integers such that the first plus the second plus three times the third is 94.
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Algebra.Com's Answer #410325 by kevwill(135) $\"\"$ $\"About$

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There is no solution with odd integers. Let 2k+1, 2k+3, and 2k + 5 be the three odd integers where k is also an integer. Then the sum of the first plus the second plus the three times the third is:
\n" ); document.write( "(2k+1) + (2k+3) + 3(2k+5) = 2k + 1 + 2k + 3 + 6k + 15 = 10k + 19\r
\n" ); document.write( "\n" ); document.write( "But since k is an integer, 10k + 19 will always be an odd number, hence there is no integer value k for which 8k + 19 = 94.
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