document.write( "Question 658274: log(e^2^(x+2))=2\r
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Algebra.Com's Answer #410246 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
log(e^2^(x+2))=2
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\n" ); document.write( "log(100)=2
\n" ); document.write( "log(e^2^(x+2))=log(100)
\n" ); document.write( "(e^2^(x+2)=100
\n" ); document.write( "take log of both sides
\n" ); document.write( "(2^(x+2)lne=ln100
\n" ); document.write( "lne=1
\n" ); document.write( "2^(x+2)=ln100
\n" ); document.write( "take log of both sides again
\n" ); document.write( "(x+2)log2=log(ln100)
\n" ); document.write( "x+2=log(ln100)/log2≈2.2033
\n" ); document.write( "x≈2.2033-2
\n" ); document.write( "x≈.2033
\n" ); document.write( "check:
\n" ); document.write( "2^(x+2)=2^(2.2033)=4.6053
\n" ); document.write( "e^4.6053≈100
\n" ); document.write( "log(e^2^(x+2))=log100=2 \n" ); document.write( "
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