document.write( "Question 658211: what is the dimension to the word problem A rectangle has a perimeter of 18 cm. Its length is 5 cm greater than its width. Find the dimension \n" ); document.write( "
Algebra.Com's Answer #410222 by colliefan(242)\"\" \"About 
You can put this solution on YOUR website!
If the width is w, the length can be written as w+5. The perimeter is 18. It is the sum of 2 lengths and 2 widths so:
\n" ); document.write( "2w + 2(w+5) = 18\r
\n" ); document.write( "\n" ); document.write( "Then simplify to solve for w. What you do to one side, you must do to the other.\r
\n" ); document.write( "\n" ); document.write( "2w + 2(w+5) = 18
\n" ); document.write( "2w+2w+10=18
\n" ); document.write( "4w+10-10=18-10
\n" ); document.write( "4w+0=8
\n" ); document.write( "4w=8
\n" ); document.write( "1/4*4w=8*1/2
\n" ); document.write( "1/4*4w=8*1/4
\n" ); document.write( "1*w=2
\n" ); document.write( "w=2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then, the length must equal w+5 or 2+5 or 7\r
\n" ); document.write( "\n" ); document.write( "Check to see that the perimeter of a rectangle with 2 sides of 2 cm and 2 sides of 7 cm equals 18.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );