document.write( "Question 658143: if measurement <2 equals 4 time the measure of <1 what is <2. ( and the picture on my worksheet is supplementary angle.)
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Algebra.Com's Answer #410186 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "Supplementary angles are pairs of angles that add up to $\"180\"$ degrees.\r
\n" ); document.write( "\n" ); document.write( "if measurement < $\"2=beta\"$ equals $\"4\"$ time the measure of < $\"1=alpha\"$ , then \r
\n" ); document.write( "\n" ); document.write( "measure< $\"beta=4%2Aalpha\"$ ........1\r
\n" ); document.write( "\n" ); document.write( " $\"alpha%2Bbeta=180\"$ ...............2
\n" ); document.write( "__________________________________solve the system... $\"beta\"$ from equation 1 plug in 2\r
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\n" ); document.write( "\n" ); document.write( " $\"alpha%2B4%2Aalpha=180\"$ ......solve for $\"alpha\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"5%2Aalpha=180\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=180%2F5\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28alpha=36%29\"$ \r
\n" ); document.write( "\n" ); document.write( "now find $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta=4%2Aalpha\"$ ........1\r
\n" ); document.write( "\n" ); document.write( " $\"beta=4%2A36\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28beta=144%29\"$ \r
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