document.write( "Question 59719This question is from textbook
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document.write( ": The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. \n" );
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Algebra.Com's Answer #41015 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+2 \n" ); document.write( "2L+2W=52 \n" ); document.write( "2(2W+2)+2W=52 \n" ); document.write( "4W+4+2W=52 \n" ); document.write( "6W=52-4 \n" ); document.write( "6W=48 \n" ); document.write( "W=48/6 \n" ); document.write( "W=8 THE WIDTH IS 8 CM. THEN \n" ); document.write( "L=2*8+2 \n" ); document.write( "L=16+2 \n" ); document.write( "L=18 THE LENGTH IS 18 CM. \n" ); document.write( "PROOF \n" ); document.write( "2*18+2*8=52 \n" ); document.write( "36+16=52 \n" ); document.write( "52=52 \n" ); document.write( " |