document.write( "Question 59719This question is from textbook
\n" ); document.write( ": The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #41015 by checkley71(8403)\"\" \"About 
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L=2W+2
\n" ); document.write( "2L+2W=52
\n" ); document.write( "2(2W+2)+2W=52
\n" ); document.write( "4W+4+2W=52
\n" ); document.write( "6W=52-4
\n" ); document.write( "6W=48
\n" ); document.write( "W=48/6
\n" ); document.write( "W=8 THE WIDTH IS 8 CM. THEN
\n" ); document.write( "L=2*8+2
\n" ); document.write( "L=16+2
\n" ); document.write( "L=18 THE LENGTH IS 18 CM.
\n" ); document.write( "PROOF
\n" ); document.write( "2*18+2*8=52
\n" ); document.write( "36+16=52
\n" ); document.write( "52=52
\n" ); document.write( "
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