document.write( "Question 658021: A CHEMIST NEEDS TO MIX AN 18% ACID SOLUTION WITH A 45% ACID SOLUTION TO OBTAIN 12 GALLONS OF A 36% ACID SOLUTION. HOW MANY GALLONS OF EACH OF THE ACID SOLUTIONS MUST HE USE?
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Algebra.Com's Answer #410113 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = gallons of 18% solution needed
\n" ); document.write( "Let \"+b+\" = gallons of 45% solution needed
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+a+%2B+b+=+12+\"
\n" ); document.write( "(2) \"+%28+.18a+%2B+.45b+%29+%2F+12+=+.36+\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "(2) \"+.18a+%2B+.45b+=+.36%2A12+\"
\n" ); document.write( "(2) \"+.18a+%2B+.45b+=+4.32+\"
\n" ); document.write( "(2) \"+18a+%2B+45b+=+432+\"
\n" ); document.write( "Multiply both sides of (1) by \"+18+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+18a+%2B+45b+=+432+\"
\n" ); document.write( "(1) \"+-18a+-+18b+=+-216+\"
\n" ); document.write( "\"+27b+=+216+\"
\n" ); document.write( "\"+b+=+8+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+12+\"
\n" ); document.write( "(1) \"+a+=+12+-+8+\"
\n" ); document.write( "(1) \"+a+=+4+\"
\n" ); document.write( "-------------
\n" ); document.write( "4 gallons of 18% solution are needed
\n" ); document.write( "8 gallons of 45% solution are needed
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.18%2A4+%2B+.45%2A8+%29+%2F+12+=+.36+\"
\n" ); document.write( "(2) \"+%28+.72+%2B+3.6+%29+%2F+12+=+.36+\"
\n" ); document.write( "(2) \"+4.32+=+.36%2A12+\"
\n" ); document.write( "(2) \"+4.32+=+4.32+\"
\n" ); document.write( "OK
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