document.write( "Question 59702: Solve by substitution\r
\n" ); document.write( "\n" ); document.write( "4x+3y=-5
\n" ); document.write( "x=y-3
\n" ); document.write( "

Algebra.Com's Answer #41011 by funmath(2933)\"\" \"About 
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Solve by substitution\r
\n" ); document.write( "\n" ); document.write( "E1) 4x+3y=-5
\n" ); document.write( "E2) x=y-3
\n" ); document.write( "Subtitute y-3 in for x in E1 and solve for y:
\n" ); document.write( "4(y-3)+3y=-5
\n" ); document.write( "4y-12+3y=-5
\n" ); document.write( "7y-12=-5
\n" ); document.write( "7y-12+12=-5+12
\n" ); document.write( "7y=7
\n" ); document.write( "7y/7=7/7
\n" ); document.write( "y=1
\n" ); document.write( "Substitute 1 in for y in E2 and solve for x:
\n" ); document.write( "x=1-3
\n" ); document.write( "x=-2
\n" ); document.write( "The solution (x,y)=(-2,1)
\n" ); document.write( "Happy Calculating!!!
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