document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=657955>Question 657955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 1 foot moe than 1/3 of its length. If the perimeter of the rectangle is 74 feet, find the area of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410077 by </B><A HREF=/tutors/aboutme.mpl?userid=lostin><B>lostin(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lostin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Width of rectangle is W and Length is L so <BR>\n" );
document.write( "W = (L/3) + 1 <BR>\n" );
document.write( "which is same as 3W = L + 3<BR>\n" );
document.write( " =>> 3W - L = 1 say it is equation 1.<BR>\n" );
document.write( "The perimeter of the rectangle is 74 feet so<BR>\n" );
document.write( "2W + 2L = 74 OR <BR>\n" );
document.write( "W+L = 37 say it is equation 2 <BR>\n" );
document.write( "solving equation 1 and 2 will give us<BR>\n" );
document.write( "W = 10 and L = 27 <BR>\n" );
document.write( "Area of retangle is W*L = 270 square feet </SPAN>\n" );
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