document.write( "Question 657593: 6^(-x) = 10^(-4x + 7)
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Algebra.Com's Answer #410028 by lwsshak3(11628)\"\" \"About 
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6^(-x) = 10^(-4x + 7)
\n" ); document.write( "take log of both sides
\n" ); document.write( "-xlog6=(-4x + 7)log10
\n" ); document.write( "log10=1
\n" ); document.write( "-xlog6=-4x + 7
\n" ); document.write( "4x-xlog6=7
\n" ); document.write( "x(4-log6)=7
\n" ); document.write( "x=7/(4-log6)
\n" ); document.write( "x≈2.1727
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