document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=657732>Question 657732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> X^2-6x+9/x^2-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409990 by </B><A HREF=/tutors/aboutme.mpl?userid=chriswen><B>chriswen(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chriswen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x^2 - 6x + 9) / (x^2 - 9)\r<BR>\n" );
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document.write( "factor\r<BR>\n" );
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document.write( "=(x-3)(x-3)/(x-3)(x+3)\r<BR>\n" );
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document.write( "FYI a^2 - b^2 = (a+b)(a-b)\r<BR>\n" );
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document.write( "cancel out (x-3)\r<BR>\n" );
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document.write( "=(x-3)/(x+3)  I think that is fully simplified.  You might also have to say that x can not equal positive or negative 3. </SPAN>\n" );
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