document.write( "Question 657563: Can you solve this problem?:\r
\n" ); document.write( "\n" ); document.write( "Paul is 20 years older than EVan. Ten years ago, Pau lwas twice as old as Evan was then. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #409958 by kevwill(135)\"\" \"About 
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Let p be Paul's age and q be Evan's age. Paul is 20 years older than Evan, so:
\n" ); document.write( "p = q + 20\r
\n" ); document.write( "\n" ); document.write( "Ten years ago, Paul was twice as old as Even was then, so:
\n" ); document.write( "(p - 10) = 2 * ( q - 10), or\r
\n" ); document.write( "\n" ); document.write( "p - 10 = 2 * q - 20\r
\n" ); document.write( "\n" ); document.write( "Substituting q + 20 for p, we have:\r
\n" ); document.write( "\n" ); document.write( "q + 20 - 10 = 2 * q - 20
\n" ); document.write( "q + 10 = 2 * q - 20\r
\n" ); document.write( "\n" ); document.write( "Subtracting q from and adding 20 to each side:\r
\n" ); document.write( "\n" ); document.write( "q + 10 - q + 20 = 2 * q - 20 - q + 20\r
\n" ); document.write( "\n" ); document.write( "30 = q\r
\n" ); document.write( "\n" ); document.write( "So Evan is 30 years old, and Paul is 30+20 = 50 years old.\r
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