document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=657267>Question 657267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the longest side of a right triangle measures 10 cm. what is the measure of the other side of the sides measure 6 cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409895 by </B><A HREF=/tutors/aboutme.mpl?userid=colliefan><B>colliefan(242)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=colliefan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is solved with the Pythagorean theorem which states that the sides of a right triangle a, b, and c fit the equation:<BR>\n" );
document.write( "a^2+b^2=c^2 where c is the hypotenuse which is the longest side.\r<BR>\n" );
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document.write( "So:\r<BR>\n" );
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document.write( "6^2+x^2=10^2<BR>\n" );
document.write( "36+x^2=100<BR>\n" );
document.write( "36+x^2-36=100-36<BR>\n" );
document.write( "36+x^2-36=100-36<BR>\n" );
document.write( "x^2+0=64<BR>\n" );
document.write( "x^2=64<BR>\n" );
document.write( "x=sqrt(64)<BR>\n" );
document.write( "x=8\r<BR>\n" );
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document.write( " </SPAN>\n" );
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