document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=657208>Question 657208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 80. One number is 26 more than the other find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409887 by </B><A HREF=/tutors/aboutme.mpl?userid=colliefan><B>colliefan(242)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=colliefan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x is one of the other numbers, x+26 is the other. Since their sum is 80, you have the following equation.\r<BR>\n" );
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document.write( "x+(x+26)=80\r<BR>\n" );
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document.write( "Remember, what you do to one side of the equation, you must do to the other.\r<BR>\n" );
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document.write( "x+(x+26)=80<BR>\n" );
document.write( "x+x+26=80<BR>\n" );
document.write( "2x+26=80<BR>\n" );
document.write( "2x+26-26=80-26<BR>\n" );
document.write( "2x+0=54<BR>\n" );
document.write( "2x=54<BR>\n" );
document.write( "2x/2=54/2<BR>\n" );
document.write( "x*1=27<BR>\n" );
document.write( "x=27\r<BR>\n" );
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document.write( "Thus, the two numbers are 27 and 53 since 27 or x + 26=53. </SPAN>\n" );
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