document.write( "Question 657227: L=a+d(n-1)
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document.write( "Solve for N \n" );
document.write( "
Algebra.Com's Answer #409884 by colliefan(242)![]() ![]() ![]() You can put this solution on YOUR website! Remember: what you do to one side of the equation, you must do to the other. If you do that, the 2 sides continue to be equal, but the equation changes form.\r \n" ); document.write( "\n" ); document.write( "L=a+d(n-1)\r \n" ); document.write( "\n" ); document.write( "Subtract a from both sides: \n" ); document.write( "L-a=a-a+d(n-1) \n" ); document.write( "L-a=0+d(n-1) \n" ); document.write( "L-a=d(n-1)\r \n" ); document.write( "\n" ); document.write( "Divide both sides by d: \n" ); document.write( "(L-a)/d=d(n-1)/d \n" ); document.write( "(L-a)/d=(n-1)d/d \n" ); document.write( "(L-a)/d=(n-1)*1 \n" ); document.write( "(L-a)/d=(n-1) \n" ); document.write( "(L-a)/d=n-1\r \n" ); document.write( "\n" ); document.write( "Add 1 to both sides: \n" ); document.write( "((L-a)/d)+1=n-1+1 \n" ); document.write( "((L-a)/d)+1=n+0 \n" ); document.write( "((L-a)/d)+1=n \n" ); document.write( "n=((L-a)/d)+1 \n" ); document.write( " |