document.write( "Question 657227: L=a+d(n-1)
\n" ); document.write( "Solve for N
\n" ); document.write( "

Algebra.Com's Answer #409884 by colliefan(242)\"\" \"About 
You can put this solution on YOUR website!
Remember: what you do to one side of the equation, you must do to the other. If you do that, the 2 sides continue to be equal, but the equation changes form.\r
\n" ); document.write( "\n" ); document.write( "L=a+d(n-1)\r
\n" ); document.write( "\n" ); document.write( "Subtract a from both sides:
\n" ); document.write( "L-a=a-a+d(n-1)
\n" ); document.write( "L-a=0+d(n-1)
\n" ); document.write( "L-a=d(n-1)\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by d:
\n" ); document.write( "(L-a)/d=d(n-1)/d
\n" ); document.write( "(L-a)/d=(n-1)d/d
\n" ); document.write( "(L-a)/d=(n-1)*1
\n" ); document.write( "(L-a)/d=(n-1)
\n" ); document.write( "(L-a)/d=n-1\r
\n" ); document.write( "\n" ); document.write( "Add 1 to both sides:
\n" ); document.write( "((L-a)/d)+1=n-1+1
\n" ); document.write( "((L-a)/d)+1=n+0
\n" ); document.write( "((L-a)/d)+1=n
\n" ); document.write( "n=((L-a)/d)+1
\n" ); document.write( "
\n" );