document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=657462>Question 657462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the measures of two supplementary angles exceeds the difference of their measures by 116 degrees. fine the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409878 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of the measures of two supplementary angles exceeds the difference of their measures by 116 degrees. find the measure of each angle. <BR>\n" );
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document.write( "Eqution:<BR>\n" );
document.write( "x + y = 180<BR>\n" );
document.write( "x+y = (x-y) + 116<BR>\n" );
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document.write( "x = 180-y<BR>\n" );
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document.write( "Substitute and solve for \"y\":<BR>\n" );
document.write( "180 = (180-y-y) + 116<BR>\n" );
document.write( "-2y = -116<BR>\n" );
document.write( "y = 58 degrees<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x + 58 = 180<BR>\n" );
document.write( "x = 122 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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