document.write( "Question 657297: Two boys who live 14 miles apart start at noon to walk toward each other at rates of 3 mph and 4 mph respectively. In how many hours will they meet? \n" ); document.write( "
Algebra.Com's Answer #409803 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Two boys who live 14 miles apart start at noon to walk toward each other at rates of 3 mph and 4 mph respectively. In how many hours will they meet? \n" ); document.write( "----- \n" ); document.write( "slower boy DATA: \n" ); document.write( "rate = 3 mph ; distance = x miles ; time = d/r = x/3 hrs \n" ); document.write( "--- \n" ); document.write( "faster boy DATA: \n" ); document.write( "rate = 4 mph ; distance = 14-x miles ; time = d/r = (14-x)/4 hrs \n" ); document.write( "------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time = time \n" ); document.write( "x/3 = (14-x)/4 \n" ); document.write( "4x = 3(14-x) \n" ); document.write( "4x = 42 - 3x \n" ); document.write( "7x = 42 \n" ); document.write( "x = 6 miles (slower boy distance) \n" ); document.write( "x/3 = 6/3 = 2 hrs (time till the boys meet) \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |