document.write( "Question 657297: Two boys who live 14 miles apart start at noon to walk toward each other at rates of 3 mph and 4 mph respectively. In how many hours will they meet? \n" ); document.write( "
Algebra.Com's Answer #409803 by stanbon(75887)\"\" \"About 
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Two boys who live 14 miles apart start at noon to walk toward each other at rates of 3 mph and 4 mph respectively. In how many hours will they meet?
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\n" ); document.write( "slower boy DATA:
\n" ); document.write( "rate = 3 mph ; distance = x miles ; time = d/r = x/3 hrs
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\n" ); document.write( "faster boy DATA:
\n" ); document.write( "rate = 4 mph ; distance = 14-x miles ; time = d/r = (14-x)/4 hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time = time
\n" ); document.write( "x/3 = (14-x)/4
\n" ); document.write( "4x = 3(14-x)
\n" ); document.write( "4x = 42 - 3x
\n" ); document.write( "7x = 42
\n" ); document.write( "x = 6 miles (slower boy distance)
\n" ); document.write( "x/3 = 6/3 = 2 hrs (time till the boys meet)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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