document.write( "Question 657226: how many quarts of pure antifreeze must be added to 2 quarts of a 30% antifreeze solution to obtaine a 60% antifreeze solution \n" ); document.write( "

Algebra.Com's Answer #409790 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = quarts of pure antifreeze needed
\n" ); document.write( " $\"+.3%2A2+=+.6+\"$ quarts of pure antifreeze in 30% solution
\n" ); document.write( "--------------
\n" ); document.write( " $\"+%28+.6+%2B+x+%29+%2F+%28+2+%2B+x+%29+=+.6+\"$
\n" ); document.write( " $\"+.6+%2B+x+=+.6%2A%28+2+%2B+x+%29+\"$
\n" ); document.write( " $\"+.6+%2B+x+=+1.2+%2B+.6x+\"$
\n" ); document.write( " $\"+x+-+.6x+=+1.2+-+.6+\"$
\n" ); document.write( " $\"+.4x+=+.6+\"$
\n" ); document.write( " $\"+x+=+3%2F2+\"$
\n" ); document.write( "1.5 quarts of pure antifreeze must be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.6+%2B+x+%29+%2F+%28+2+%2B+x+%29+=+.6+\"$
\n" ); document.write( " $\"+%28+.6+%2B+1.5+%29+%2F+%28+2+%2B+1.5+%29+=+.6+\"$
\n" ); document.write( " $\"+2.1+%2F+3.5+=+.6+\"$
\n" ); document.write( " $\"+2.1+=+.6+%2A+3.5+\"$
\n" ); document.write( " $\"+2.1+=+2.1+\"$
\n" ); document.write( "OK \n" ); document.write( "

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