document.write( "Question 59516This question is from textbook
\n" ); document.write( ": (76) Magazine sales. A company specializing in magazine sales over the telephone found that in 2500 phone calls, 360 resulted in sales and were made by male callers, and 480 resulted in sales and were made by female callers. If the company gets twice as many sales per call with a woman’s voice than with man’s voice, then how many of the 2500 calls were made by female?\r
\n" ); document.write( "\n" ); document.write( "Please help! I am stuck on this problems for hours!
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Algebra.Com's Answer #40977 by venugopalramana(3286)\"\" \"About 
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A company specializing in magazine sales over the telephone found that in 2500 phone calls, 360 resulted in sales and were made by male callers, and 480 resulted in sales and were made by female callers. If the company gets twice as many sales per call with a woman’s voice than with man’s voice, then how many of the 2500 calls were made by female?
\n" ); document.write( "Please help! I am stuck on this problems for hours!
\n" ); document.write( "LET CALLS MADE BY FEMALE =X
\n" ); document.write( "CALLS MADE BY MALE =2500-X
\n" ); document.write( "LET SUCCESS RATE WITH MALES = Y/CALL
\n" ); document.write( "SUCCESS RATE WITH FEMALES = 2Y/CALL
\n" ); document.write( "ORDERS FROM FEMALE CALLS = X*2Y=480.................1
\n" ); document.write( "ORDERS FROM MALE CALLS = (2500-X)Y=360...................2
\n" ); document.write( "EQN.1/EQN.2
\n" ); document.write( "2XY/(2500-X)Y=480/360 = 4/3
\n" ); document.write( "3*2X=(2500-X)4=10000-4X
\n" ); document.write( "6X+4X=10000
\n" ); document.write( "10X=10000
\n" ); document.write( "X=1000
\n" ); document.write( "HENCE 1000 CALLS WERE MADE BY FEMALES.
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