document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59623>Question 59623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I submitted this problem earlier today but made a mistake.  The correct problem is:  Find the dimensions of a box whose volume is 196 cu. in., whose surface area is 280 sq. in., and whose LENGTH is twice its width.\r<BR>\n" );
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document.write( "I got 2 equations:<BR>\n" );
document.write( "196=2W^2H  (W is width and H is height)<BR>\n" );
document.write( "280=4W^2+6WH\r<BR>\n" );
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document.write( "I solved the first equation for H and substituted it in the 2nd equation, ending up with:<BR>\n" );
document.write( "4W^3-280W+588=0<BR>\n" );
document.write( "I can't figure out where to go from here. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40976 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40976\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I submitted this problem earlier today but made a mistake. The correct problem is: Find the dimensions of a box whose volume is 196 cu. in., whose surface area is 280 sq. in., and whose LENGTH is twice its width.<BR>\n" );
document.write( "L=2W<BR>\n" );
document.write( "V= LWH= 2W^2H=196<BR>\n" );
document.write( "S.A= 2[LW+WH+HL]=280<BR>\n" );
document.write( "2W^2+WH+2WH=140<BR>\n" );
document.write( "2W^2+3WH=140\r<BR>\n" );
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document.write( "I got 2 equations:<BR>\n" );
document.write( "196=2W^2H (W is width and H is height)..OK<BR>\n" );
document.write( "W^2H=98...........H=98/W^2<BR>\n" );
document.write( "280=4W^2+6WH...OK<BR>\n" );
document.write( "2W^2+3WH=140<BR>\n" );
document.write( "2W^2+3W*98/W^2=140<BR>\n" );
document.write( "2W^3+294=140W<BR>\n" );
document.write( "2W^3-140W+294=0<BR>\n" );
document.write( "I solved the first equation for H and substituted it in the 2nd equation, ending up with:<BR>\n" );
document.write( "4W^3-280W+588=0....OK<BR>\n" );
document.write( "W^3-70W+147=0<BR>\n" );
document.write( "TAKING FACTORS OF 147 ...WE HAVE 147=1*3*7*7<BR>\n" );
document.write( "HENCE CHECKING F(1),F(3),F(7)<BR>\n" );
document.write( "WE FIND F(7) = 7^3-70*7+147=0<BR>\n" );
document.write( "HENCE W=7<BR>\n" );
document.write( "L=2*7=14<BR>\n" );
document.write( "H= 98/(7*7)=2<BR>\n" );
document.write( "CHECK....V=14*7*2=196...OK<BR>\n" );
document.write( "S.A. = 2[14*7+14*2+7*2]=2(98+28+14)=280...OK\r<BR>\n" );
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document.write( "I can't figure out where to go from here. </SPAN>\n" );
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