document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7370>Question 7370</A>: <I><SPAN STYLE=\"word-break: break-all;\">  problem:<BR>\n" );
document.write( "the area of a circle is 25 meters. find the radius of the circle.<BR>\n" );
document.write( "i solved to this point.<BR>\n" );
document.write( "7.96 m (squared)= r (squared)\r<BR>\n" );
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document.write( "the books says answer is r=2.82\r<BR>\n" );
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document.write( "i need to understand the step on how they got the answer<BR>\n" );
document.write( "thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4097 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4097\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, your first step is just fine:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+%2825%2F3.14%29 ALIGN=MIDDLE  ALT=\"r%5E2+=+%2825%2F3.14%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+7.96+ ALIGN=MIDDLE  ALT=\"r%5E2+=+7.96+\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now take the square root of both sides.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%287.96%29 ALIGN=MIDDLE  ALT=\"r+=+sqrt%287.96%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "r = 2.82 meters, approximately. </SPAN>\n" );
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