document.write( "Question 656843: the length of a rectangle is three less than twice the width and its equal to 44 sq. cm .find the dimension of rectangle. \n" ); document.write( "
Algebra.Com's Answer #409688 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-3 \n" ); document.write( "PERIMETER=L*W \n" ); document.write( "44=(2W-3)W \n" ); document.write( "44=2W^2-3W \n" ); document.write( "2W^2-3W-44=0 \n" ); document.write( "(2W-11)(W+4)=0 \n" ); document.write( "2W-11=0 \n" ); document.write( "W=11/2 \n" ); document.write( "W=5.5 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*5.5-3 \n" ); document.write( "L=11-3 \n" ); document.write( "L=8 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "44=8*5.5 \n" ); document.write( "44=44\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |