document.write( "Question 656843: the length of a rectangle is three less than twice the width and its equal to 44 sq. cm .find the dimension of rectangle. \n" ); document.write( "
Algebra.Com's Answer #409688 by checkley79(3341)\"\" \"About 
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L=2W-3
\n" ); document.write( "PERIMETER=L*W
\n" ); document.write( "44=(2W-3)W
\n" ); document.write( "44=2W^2-3W
\n" ); document.write( "2W^2-3W-44=0
\n" ); document.write( "(2W-11)(W+4)=0
\n" ); document.write( "2W-11=0
\n" ); document.write( "W=11/2
\n" ); document.write( "W=5.5 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*5.5-3
\n" ); document.write( "L=11-3
\n" ); document.write( "L=8 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "44=8*5.5
\n" ); document.write( "44=44\r
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