document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=656787>Question 656787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when asked her age, Miss Grundy refused to tell. After being begged for a hint, however, she finally admitted that in 12 years she hoped to br three times as old as she was 42 years ago. \r<BR>\n" );
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document.write( "how old is she now ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409663 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when asked her age, Miss Grundy refused to tell. After being begged for a hint, however, she finally admitted that in 12 years she hoped to br three times as old as she was 42 years ago. <BR>\n" );
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document.write( "Let a = her age now<BR>\n" );
document.write( "In 12 years her age will be a + 12<BR>\n" );
document.write( "Her age 42 years ago = a - 42<BR>\n" );
document.write( "And her age in 12 years is 3 times her age 42 years ago:<BR>\n" );
document.write( "a + 12 = 3(a - 42)<BR>\n" );
document.write( "Solve for a:<BR>\n" );
document.write( "a + 12 = 3a - 126<BR>\n" );
document.write( "2a = 138<BR>\n" );
document.write( "a = 69<BR>\n" );
document.write( "So she is 69 years old now.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "69+12 = 81 = 3(69-42) = 3(27)<BR>\n" );
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