document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59663>Question 59663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When 16b2 + 10b - 21 is factored, one factor is: \r<BR>\n" );
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document.write( " 4b - 7 <BR>\n" );
document.write( " 8b + 7 <BR>\n" );
document.write( " 2b - 3 <BR>\n" );
document.write( " 16b + 3 <BR>\n" );
document.write( " none of these  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40965 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40965\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When 16b^2 + 10b - 21 is factored, one factor is: \r<BR>\n" );
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document.write( " 4b - 7 <BR>\n" );
document.write( " 8b + 7 <BR>\n" );
document.write( " 2b - 3 <BR>\n" );
document.write( " 16b + 3 <BR>\n" );
document.write( " (none of these) <---answer<BR>\n" );
document.write( ":<BR>\n" );
document.write( "16b^2+10b-21  This is the ac method.  a*c=16*-21=-336  replace b, (10) with two numbers that multiply to give you -336, but add to give you 10.  I used the prime factors of 336 to find them.<BR>\n" );
document.write( "16b^2+24b-14b-21<BR>\n" );
document.write( "(16b^2+24b)+(-14b-21)<BR>\n" );
document.write( "8b(2b+3)-7(2b+3)<BR>\n" );
document.write( "(2b+3)(8b-7)  <---Neither of these factors is a choice.<BR>\n" );
document.write( "Happy Calculating!!!  </SPAN>\n" );
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