document.write( "Question 656372: x^4/3 = 256
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Algebra.Com's Answer #409586 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "The solution to this problem will have the form: \n" ); document.write( "x = something \n" ); document.write( "The exponent on this \"x\" is a 1. So one way to solve this problem is to figure out how to turn the exponent we have, 4/3, into the exponent we want, 1. We have several rules for exponents which show us how exponents can be changed. The rule we need is the power of a power rule. We will raise both sides of the equation by the same power so that the exponent on the left turns into a 1: \n" ); document.write( " \n" ); document.write( "The question now is, what should \"n\" be in order for the exponent on the left to turn into a 1? The rule tells us that we should multiply these exponents. So 4/3 times what number results in a 1? Since the product of all reciprocals is a 1, we can use the reciprocal of 4/3, which is 3/4, to get the desired exponent: \n" ); document.write( " \n" ); document.write( "On the left we get what we wanted, x. All that remains is to simplify the right side as much as possible. If you have trouble with fractional or negative exponents, I find that it can help if you factor the exponent in a special way:
\n" ); document.write( " \n" ); document.write( "Each factor tells us an operation to perform. The factor of 3 tells us that we will cube a number and the factor of 1/4 (if you remember your fractional exponents) means find a 4th root. An advantage of factoring the exponent is that these operations can be done in any order. We can cube 256 first and then find a 4th root: \n" ); document.write( " \n" ); document.write( "or we can find a 4th root first and then cube it: \n" ); document.write( " \n" ); document.write( "With a little investigation we can find that 256 is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "And cubing 4 is simple: \n" ); document.write( " |