document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=656022>Question 656022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the method of substitution to solve the system of linear equations\r<BR>\n" );
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document.write( "3x-y=5<BR>\n" );
document.write( "7x-2y=12\r<BR>\n" );
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document.write( "the solution is _______(order pair) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409544 by </B><A HREF=/tutors/aboutme.mpl?userid=MathDazed><B>MathDazed(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathDazed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathDazed><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x - y = 5........(i)<BR>\n" );
document.write( "7x - 2y = 12......(ii)\r<BR>\n" );
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document.write( "To use the substitution method, you will have to solve for one of the variables. I chose to use equation (i) and solve for y.<BR>\n" );
document.write( "3x - y + y = 5 + y<BR>\n" );
document.write( "3x = 5 + y<BR>\n" );
document.write( "3x - 5 = 5 - 5 + y<BR>\n" );
document.write( "3x - 5 = y.........(iii)\r<BR>\n" );
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document.write( "Substitute equation (iii) into equation (ii)\r<BR>\n" );
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document.write( "7x - 2(3x-5) = 12<BR>\n" );
document.write( "7x - 6x + 10 = 12<BR>\n" );
document.write( "x + 10 - 10 = 12 - 10<BR>\n" );
document.write( "x = 2\r<BR>\n" );
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document.write( "Substitute x = 2 into (iii)<BR>\n" );
document.write( "3(2) - 5 = y<BR>\n" );
document.write( "6 - 5 = y<BR>\n" );
document.write( "y = 1\r<BR>\n" );
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document.write( "Solution (2,1) </SPAN>\n" );
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