document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=656434>Question 656434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> evaluate 4^0-8^(2/3)+9^(1/2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409513 by </B><A HREF=/tutors/aboutme.mpl?userid=Shana-D77><B>Shana-D77(132)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shana-D77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shana-D77><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "evaluate 4^0-8^(2/3)+9^(1/2)<BR>\n" );
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document.write( "Let's break this into a few parts:<BR>\n" );
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document.write( "First part: 4^0 = 1.  All numbers raised ot the zero power are equal to 1. Always.  We can go into this more if you want (just email me).<BR>\n" );
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document.write( "Second part: 8^(2/3)<BR>\n" );
document.write( "8^(2/3) = (8^2)(8^(1/3))<BR>\n" );
document.write( "8^2 = 64 and<BR>\n" );
document.write( "8^(1/3) = 2  [because 2*2*2 = 8],<BR>\n" );
document.write( "so 8^(2/3) = 64*2 = 128<BR>\n" );
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document.write( "Third part: 9^(1/2)<BR>\n" );
document.write( "Anything raised to the 1/2 is a square root.  25^(1/2) = 5, for example.<BR>\n" );
document.write( "So, 9^(1/2) = 3<BR>\n" );
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document.write( "Put the pieces together:<BR>\n" );
document.write( "0 - 128 + 3 = <BR>\n" );
document.write( "-128 + 3 =<BR>\n" );
document.write( "-125 </SPAN>\n" );
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