document.write( "Question 656388: Please I am very confused with this question:\r
\n" ); document.write( "\n" ); document.write( "What type of real number is the product of an irrational number times a rational numbers?\r
\n" ); document.write( "\n" ); document.write( "My guesses are that the product is an irrational number because for example the\r
\n" ); document.write( "\n" ); document.write( "{{sqrt(16) * sqrt(8) = 6.72...}} which can't be express in form of a fraction which wouldn't make it a rational number\r
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Algebra.Com's Answer #409497 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Seems reasonable. Let's assume the opposite is possible; that is, assume that there is a rational number (other than zero) and an irrational number such that the product of the two is rational.\r
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\n" ); document.write( "\n" ); document.write( "Let be the set of irrational numbers and let be a number such that . Let be a number such that .\r
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\n" ); document.write( "\n" ); document.write( " means that \r
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\n" ); document.write( "\n" ); document.write( "If the product , then there must be integers \r
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\n" ); document.write( "\n" ); document.write( "Substituting:\r
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\n" ); document.write( "\n" ); document.write( "Which is to say:\r
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\n" ); document.write( "\n" ); document.write( "But since the integers are closed under multiplication, must be the quotient of integers and therefore rational. This contradicts the initial assumption that is irrational. Therefore, reductio ad absurdum, the product of a rational number and an irrational number cannot be rational.
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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