document.write( "Question 656343: Answers for Admission Tickets To A Football Game Were 60 Cents For Adults And 25 Cents For Children. Receipts For The Day Showed That 280 Persons Attended And $140 Was Collected. How Many Adults And How Many Children attended? \n" ); document.write( "
Algebra.Com's Answer #409477 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! A+C=280 \n" ); document.write( "OR \n" ); document.write( "A=280-C \n" ); document.write( ".60A+.25C=140 \n" ); document.write( ".60(280-C)+.25C=140 \n" ); document.write( "168-.60C+.25C=140 \n" ); document.write( "-.35C=140-168 \n" ); document.write( "-.35C=-28 \n" ); document.write( "C=-28/-.35 \n" ); document.write( "C=80 CHILDREN BOUGHT TICKETS. \n" ); document.write( "A+80=280 \n" ); document.write( "A=280-80 \n" ); document.write( "A=200 ADULT BOUGHT TICKETS. \n" ); document.write( "PROOF: \n" ); document.write( ".60*200+.25*80=140 \n" ); document.write( "120+20=140 \n" ); document.write( "140=140 \n" ); document.write( " |