document.write( "Question 656303: Find the value of K so that the graph of 21y-kx=4 and the line containing the points (5,-8) and (2,4) are parallel
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Algebra.Com's Answer #409443 by shweta(56)\"\" \"About 
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In equation: 21y-kx=4, we can find the slope m1 by framing it in the form of
\n" ); document.write( "y= mx+c ,where m is the slope
\n" ); document.write( " 21y-kx=4
\n" ); document.write( " 21y= 4+kx
\n" ); document.write( " 21y= kx+4
\n" ); document.write( " y= kx/21+4/21
\n" ); document.write( "here m1= k/21 ...(1)
\n" ); document.write( "Now slope m2 of line containing the points (5,-8) ,(2,4)
\n" ); document.write( " m2= (y2- y1)/(x2- x1)
\n" ); document.write( " m2= 4-(-8)/2-5
\n" ); document.write( " m2= 4+8/(-3)
\n" ); document.write( " m2= -12/3
\n" ); document.write( " m2= -4 ...(2)
\n" ); document.write( "Since the graph and the line are parallel, m1= m2
\n" ); document.write( " k/21= -4
\n" ); document.write( " k= -4*21
\n" ); document.write( " k= -84 \n" ); document.write( "
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