document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=656289>Question 656289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fraction </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409434 by </B><A HREF=/tutors/aboutme.mpl?userid=shweta><B>shweta(56)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shweta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the fraction be N/D<BR>\n" );
document.write( "                    <BR>\n" );
document.write( "D= N-7(given)<BR>\n" );
document.write( "fraction:N/N-7   ..1<BR>\n" );
document.write( "When N+3/D+3 = 15/8<BR>\n" );
document.write( "            <BR>\n" );
document.write( " N+3/N-7+3 =15/8<BR>\n" );
document.write( " N+3/N-4 = 15/8<BR>\n" );
document.write( " On cross- multiplication,<BR>\n" );
document.write( " 8*(N+3) = 15*(N-4)<BR>\n" );
document.write( " 8N+  24 = 15N - 60<BR>\n" );
document.write( " 24+60 = 15N -8N<BR>\n" );
document.write( " 7N = 84<BR>\n" );
document.write( " N= 84/7<BR>\n" );
document.write( " N= 12<BR>\n" );
document.write( " D= N-7<BR>\n" );
document.write( " D= 12-7= 5<BR>\n" );
document.write( "So the original fraction is 12/5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );