document.write( "Question 656289: in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fraction \n" ); document.write( "
Algebra.Com's Answer #409432 by stanbon(75887) ![]() You can put this solution on YOUR website! in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fraction \n" ); document.write( "---- \n" ); document.write( "Let the numerator be \"x\". \n" ); document.write( "Then denominator is \"x-7\" \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "(x+3)/(x-7+3) = 15/8 \n" ); document.write( "----- \n" ); document.write( "(x+3)/(x-4) = 15/8 \n" ); document.write( "8x + 24 = 15x - 60 \n" ); document.write( "7x = 84 \n" ); document.write( "x = 12 \n" ); document.write( "---- \n" ); document.write( "Fraction: x/(x-7) = 12/5 \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |