document.write( "Question 656289: in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fraction \n" ); document.write( "
Algebra.Com's Answer #409432 by stanbon(75887)\"\" \"About 
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in a certain fraction, the denominater is 7 less than the numberator. if 3 is added to both the numerator and denominater the resulting fraction is (15/8). what is the original fraction
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\n" ); document.write( "Let the numerator be \"x\".
\n" ); document.write( "Then denominator is \"x-7\"
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\n" ); document.write( "Equation:
\n" ); document.write( "(x+3)/(x-7+3) = 15/8
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\n" ); document.write( "(x+3)/(x-4) = 15/8
\n" ); document.write( "8x + 24 = 15x - 60
\n" ); document.write( "7x = 84
\n" ); document.write( "x = 12
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\n" ); document.write( "Fraction: x/(x-7) = 12/5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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