document.write( "Question 656275: 10 years ago, I was 14 times as old as my daughter. Now I am 4 times as old as she is. \n" ); document.write( "
Algebra.Com's Answer #409428 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
How old am I now?
\n" ); document.write( "Let \"+x+\" = my age now
\n" ); document.write( "\"+x+-+10+\" = my age 10 years ago
\n" ); document.write( "Let \"+y+\" = my Daughter's age now
\n" ); document.write( "\"+y+-+10+\" = my Daughter's age 10 years ago
\n" ); document.write( "----------
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+x+-+10+=+14%2A%28+y+-+10+%29+\"
\n" ); document.write( "(2) \"+x+=+4y+\"
\n" ); document.write( "-------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+4y+-+10+=+14%2A%28+y+-+10+%29+\"
\n" ); document.write( "(1) \"+4y+-+10+=+14y+-+140+\"
\n" ); document.write( "(1) \"+14y+-+4y+=+140+-+10+\"
\n" ); document.write( "(1) \"+10y+=+130+\"
\n" ); document.write( "(1) \"+y+=+13+\"
\n" ); document.write( "and. since
\n" ); document.write( "(2) \"+x+=+4y+\"
\n" ); document.write( "(2) \"+x+=+4%2A13+\"
\n" ); document.write( "(2) \"+x+=+52+\"
\n" ); document.write( "I am 52 now and my Daughter is 13
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+x+-+10+=+14%2A%28+y+-+10+%29+\"
\n" ); document.write( "(1) \"+52+-+10+=+14%2A%28+13+-+10+%29+\"
\n" ); document.write( "(1) \"+42+=+14%2A3+\"
\n" ); document.write( "(1) \"+42+=+42+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );