document.write( "Question 656237: In your pocket, you have a handful of change in nickels, dimes, and quarters that totals $3.10. There are four more dimes than nickels, and three times as many quarters as nickels. Find the number of each type of coin. \n" ); document.write( "
Algebra.Com's Answer #409420 by htmentor(1343)\"\" \"About 
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In your pocket, you have a handful of change in nickels, dimes, and quarters that totals $3.10. There are four more dimes than nickels, and three times as many quarters as nickels. Find the number of each type of coin.
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\n" ); document.write( "Let d = the number of dimes
\n" ); document.write( "Let n = the number of nickels
\n" ); document.write( "Then the number of quarters = 3n
\n" ); document.write( "We can write the following equation for the total amount:
\n" ); document.write( "5n + 10d + 25(3n) = 310
\n" ); document.write( "Given: four more dimes than nickels -> d = n+4
\n" ); document.write( "5n + 10(n+4) + 75n = 310
\n" ); document.write( "Solve for n:
\n" ); document.write( "5n + 10n + 40 + 75n = 310
\n" ); document.write( "90n = 270
\n" ); document.write( "n = 3
\n" ); document.write( "So the number of nickels = 3
\n" ); document.write( "The number of dimes = 3+4 = 7
\n" ); document.write( "The number of quarters = 3*3 = 9
\n" ); document.write( "Check:
\n" ); document.write( "3*5 + 7*10 + 9*25 = 310 \n" ); document.write( "
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