document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59685>Question 59685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (rs) radical sign\r<BR>\n" );
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document.write( "(rs)4x+12    +4=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40938 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The question is quite confusing because we need to know whether the radical is there for the entire expression that is, \r<BR>\n" );
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document.write( "rs(4x + 12 + 4) or only for 4x + 12. \r<BR>\n" );
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document.write( "I will solve them for you in both the ways.\r<BR>\n" );
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document.write( "1st METHOD\r<BR>\n" );
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document.write( "RS(4x+ 12 + 4) = 0\r<BR>\n" );
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document.write( "Taking square root on both sides of the above equation, we get: \r<BR>\n" );
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document.write( "4x + 12 + 4 = 0\r<BR>\n" );
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document.write( "==> 4x + 16 = 0\r<BR>\n" );
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document.write( "Subtracting 16 from both sides of the above equation, we get: \r<BR>\n" );
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document.write( "==> 4x = - 16\r<BR>\n" );
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document.write( "==> x = - 16/4\r<BR>\n" );
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document.write( "==> x = -4\r<BR>\n" );
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document.write( "2nd METHOD \r<BR>\n" );
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document.write( "RS(4x + 12) + 4 = 0 \r<BR>\n" );
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document.write( "Subtracting 4 from both sides of the above equation, we get: \r<BR>\n" );
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document.write( "==> RS(4x + 12)  = -4 \r<BR>\n" );
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document.write( "Now, Squaring both sides of the above equation, we get: \r<BR>\n" );
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document.write( "==> (4x + 12) = (-4)* (-4) \r<BR>\n" );
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document.write( "==> (4x + 12) = 16 \r<BR>\n" );
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document.write( "Now, Subtracting 12 on both sides of the above equation, we get: \r<BR>\n" );
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document.write( "==> 4x = 16 - 12\r<BR>\n" );
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document.write( "==> 4x = 4\r<BR>\n" );
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document.write( "==> x = 4/4 \r<BR>\n" );
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document.write( "==> x = 1 \r<BR>\n" );
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document.write( "Hence the solution. <BR>\n" );
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