document.write( "Question 656141: The sum of three numbers is 496. The second number is 8/15 of the first, the first number is less than the third to 2 3/4 times, find each number. \n" ); document.write( "
Algebra.Com's Answer #409368 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Three numbers: a, b, c \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "The sum of three numbers is 496. \n" ); document.write( "a + b + c = 496 \n" ); document.write( ": \n" ); document.write( "The second number is 8/15 of the first, \n" ); document.write( "b = \n" ); document.write( ": \n" ); document.write( "the first number is less than the third to 2 3/4 times, \n" ); document.write( "c = 2 \n" ); document.write( "same as \n" ); document.write( "c = \n" ); document.write( ": \n" ); document.write( "Replace b and c in the 1st equation \n" ); document.write( "a + \n" ); document.write( "Get rid of those annoying fractions, multiply by 60, results \n" ); document.write( "60a + 4(8a) + 15(11a) = 60(496) \n" ); document.write( "60a + 32a + 165a = 29760 \n" ); document.write( "257a = 29760 \n" ); document.write( "a = 29760/257 \n" ); document.write( "a ~ 115.80; I was hoping for an integer here, but we'll just charge ahead \n" ); document.write( "b = (8/15)*115.8 ~ 61.75 \n" ); document.write( "c = (11/4}}}* 115.8 ~ 318.45 \n" ); document.write( ": \n" ); document.write( "See if these devils add up! \n" ); document.write( "115.8 \n" ); document.write( " 61.75 \n" ); document.write( "318.45 \n" ); document.write( "-------- \n" ); document.write( "496.00! \n" ); document.write( ": \n" ); document.write( "The only thing I can think of is, I misinterpreted: \n" ); document.write( "\" the first number is less than the third to 2 3/4 times, \" \n" ); document.write( "Certainly a confusing way to say whatever they were trying to say. \n" ); document.write( ": \n" ); document.write( "Please let me know if you find out about this. Thanks. C\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |