document.write( "Question 656140: solving by elimination
\n" ); document.write( "5x-7y=-49
\n" ); document.write( "3x+9y=-3
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Algebra.Com's Answer #409358 by MathLover1(20850)\"\" \"About 
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"5%2Ax-7%2Ay=-49\"
\n" ); document.write( " \"3%2Ax%2B9%2Ay=-3\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and 3 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 5 and 3 is 15, we need to multiply both sides of the top equation by 3 and multiply both sides of the bottom equation by -5 like this:
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\n" ); document.write( " \"3%2A%285%2Ax-7%2Ay%29=%28-49%29%2A3\" Multiply the top equation (both sides) by 3
\n" ); document.write( " \"-5%2A%283%2Ax%2B9%2Ay%29=%28-3%29%2A-5\" Multiply the bottom equation (both sides) by -5
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"15%2Ax-21%2Ay=-147\"
\n" ); document.write( " \"-15%2Ax-45%2Ay=15\"
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\n" ); document.write( " Notice how 15 and -15 add to zero (ie \"15%2B-15=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2815%2Ax-15%2Ax%29-21%2Ay-45%2Ay%29=-147%2B15\"
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\n" ); document.write( " \"%2815-15%29%2Ax-21-45%29y=-147%2B15\"
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\n" ); document.write( " \"cross%2815%2B-15%29%2Ax%2B%28-21-45%29%2Ay=-147%2B15\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-66%2Ay=-132\"
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\n" ); document.write( " \"y=-132%2F-66\" Divide both sides by \"-66\" to solve for y
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\n" ); document.write( " \"y=2\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"5%2Ax-7%2Ay=-49\" to solve for x
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\n" ); document.write( " \"5%2Ax-7%282%29=-49\" Plug in \"y=2\"
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\n" ); document.write( " \"5%2Ax-14=-49\" Multiply
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\n" ); document.write( " \"5%2Ax=-49%2B14\" Subtract \"-14\" from both sides
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\n" ); document.write( " \"5%2Ax=-35\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F5%29%285%29%29%2Ax=%28-35%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5\" on the left side.
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\n" ); document.write( " \"x=-7\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-7\", \"y=2\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-7\", \"2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"5%2Ax-7%2Ay=-49\"
\n" ); document.write( " \"3%2Ax%2B9%2Ay=-3\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"5%2Ax-7%2Ay=-49\" (red) \"3%2Ax%2B9%2Ay=-3\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-7\",\"2\"). This verifies our answer.
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