document.write( "Question 59643: What is the solution to x/3+(2x+4)/4=(x-1)/6-(3-2x)/2 \n" ); document.write( "
Algebra.Com's Answer #40933 by praseena(37)\"\" \"About 
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Here we have to solve the following problem,
\n" ); document.write( "x/3+(2x+4)/4= (x-1)/6 -(3-2x)
\n" ); document.write( "Multiply both sides by the lowest common multiple of 3,4,6,2, which is 12
\n" ); document.write( "12(x/3)+12(2x+4)/4=12(x-1)/6 -12(3-2x)/2
\n" ); document.write( "now simplify.
\n" ); document.write( "Then it comes like this\r
\n" ); document.write( "\n" ); document.write( "4x + 3(2x+4) = 2(x-1)-6(3-2x)
\n" ); document.write( "4x + 6x + 12 = 2x -2 - 18+ 12x
\n" ); document.write( "10x + 12 = 14x - 20
\n" ); document.write( "subtract 10x from both sides
\n" ); document.write( "then it is 12 = 4x - 20
\n" ); document.write( "add 20 to both sides
\n" ); document.write( "32 = 4x
\n" ); document.write( "divide both sides by 4
\n" ); document.write( "then it comes, x = 32/4 = 8
\n" ); document.write( "so the solution is x = 8 \r
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