document.write( "Question 655680: I get different answers depending on how I simplify the expression \"5%5E%283log%2825%2Ca%29%29\". This shows me that I must be awfully confused about log rules. WolframAlpha gives \"a%5E%283%2F2%29\", which I figured out can be done thusly:\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29=x\"
\n" ); document.write( "\"3log%2825%2Ca%29=log%285%2Cx%29\"
\n" ); document.write( "\"3log%285%2Ca%29%2Flog%285%2C25%29=log%285%2Cx%29\"
\n" ); document.write( "\"%283%2F2%29%2Alog%285%2Ca%29=log%285%2Cx%29%29\"
\n" ); document.write( "\"log%285%2C%28a%5E%283%2F2%29%29%29=log%285%2Cx%29\"
\n" ); document.write( "\"a%5E%283%2F2%29=x\"\r
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\n" ); document.write( "\n" ); document.write( "If I do it another way, I get my answer as \"a%5E3-25\". Here is how I did that:\r
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\n" ); document.write( "\n" ); document.write( "But if I do it another way, I get the answer as 5^(2/3)+a. See:\r
\n" ); document.write( "\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29=x\"
\n" ); document.write( "\"3log%2825%2Ca%29=log%285%2Cx%29\"
\n" ); document.write( "\"3=log%285%2Cx%29%2Flog%2825%2Ca%29\"
\n" ); document.write( "\"3=log%285%2Cx%29%2F%28log%285%2Ca%29%2Flog%285%2C25%29%29\"
\n" ); document.write( "\"3=log%285%2Cx%29%2Flog%285%2C%28a-25%29%29\"
\n" ); document.write( "\"3=log%285%2C%28x-a%2B25%29%29\"
\n" ); document.write( "\"5%5E3=x-a%2B25\"
\n" ); document.write( "\"5%5E3-25%2Ba=x\"
\n" ); document.write( "\"100%2Ba=x\"\r
\n" ); document.write( "\n" ); document.write( "And even a third answer:\r
\n" ); document.write( "\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29=x\"
\n" ); document.write( "\"3log%2825%2Ca%29=log%285%2Cx%29\"
\n" ); document.write( "\"3log%285%2Ca%29%2Flog%285%2C25%29=log%285%2Cx%29\"
\n" ); document.write( "\"%283%2F2%29%2Alog%285%2Ca%29=log%285%2Cx%29%29\"
\n" ); document.write( "\"3%2F2=log%285%2Cx%29%2Flog%285%2Ca%29\"
\n" ); document.write( "\"3%2F2=log%285%2C%28x-a%29%29\"
\n" ); document.write( "\"5%5E%283%2F2%29=x-a\"
\n" ); document.write( "\"5%5E%283%2F2%29%2Ba=x\"
\n" ); document.write( "

Algebra.Com's Answer #409257 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
I did it and also got: \"a%5E%283%2F2%29\". Therefore: \"5%5E%283log%2825%2Ca%29%29\" = \"a%5E%283%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "This is the correct answer and can be proven as follows:\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29\" ------ \"5%5E%28log%2825%2Ca%5E3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substituting \"25\" for a in \"5%5E%28log%2825%2Ca%5E3%29%29\" results in: \"5%5E%28log%2825%2C25%5E3%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "Since \"log%2825%2C25%5E3%29\" = 3, then \"5%5E%28log%2825%2C25%5E3%29%29\" = \"5%5E3\", or \"highlight%28125%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now, substituting \"25\" for a into the simplified version/answer of \"a%5E%283%2F2%29\" gives us: \"25%5E%283%2F2%29\" ----- \"%28sqrt%2825%29%29%5E3\" ------ \"5%5E3\", or \"highlight%28125%29\".\r
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\n" ); document.write( "\n" ); document.write( "This clearly proves that your 1st answer that \"5%5E%283log%2825%2Ca%29%29\" simplifies to \"highlight_green%28a%5E%283%2F2%29%29\" is unequivocally 100% correct. \r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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