document.write( "Question 655680: I get different answers depending on how I simplify the expression \"5%5E%283log%2825%2Ca%29%29\". This shows me that I must be awfully confused about log rules. WolframAlpha gives \"a%5E%283%2F2%29\", which I figured out can be done thusly:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29=x\"
\n" ); document.write( "\"3log%2825%2Ca%29=log%285%2Cx%29\"
\n" ); document.write( "\"3log%285%2Ca%29%2Flog%285%2C25%29=log%285%2Cx%29\"
\n" ); document.write( "\"%283%2F2%29%2Alog%285%2Ca%29=log%285%2Cx%29%29\"
\n" ); document.write( "\"log%285%2C%28a%5E%283%2F2%29%29%29=log%285%2Cx%29\"
\n" ); document.write( "\"a%5E%283%2F2%29=x\"\r
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\n" ); document.write( "\n" ); document.write( "If I do it another way, I get my answer as \"a%5E3-25\". Here is how I did that:\r
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\n" ); document.write( "\n" ); document.write( "But if I do it another way, I get the answer as 5^(2/3)+a. See:\r
\n" ); document.write( "\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29=x\"
\n" ); document.write( "\"3log%2825%2Ca%29=log%285%2Cx%29\"
\n" ); document.write( "\"3=log%285%2Cx%29%2Flog%2825%2Ca%29\"
\n" ); document.write( "\"3=log%285%2Cx%29%2F%28log%285%2Ca%29%2Flog%285%2C25%29%29\"
\n" ); document.write( "\"3=log%285%2Cx%29%2Flog%285%2C%28a-25%29%29\"
\n" ); document.write( "\"3=log%285%2C%28x-a%2B25%29%29\"
\n" ); document.write( "\"5%5E3=x-a%2B25\"
\n" ); document.write( "\"5%5E3-25%2Ba=x\"
\n" ); document.write( "\"100%2Ba=x\"\r
\n" ); document.write( "\n" ); document.write( "And even a third answer:\r
\n" ); document.write( "\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29=x\"
\n" ); document.write( "\"3log%2825%2Ca%29=log%285%2Cx%29\"
\n" ); document.write( "\"3log%285%2Ca%29%2Flog%285%2C25%29=log%285%2Cx%29\"
\n" ); document.write( "\"%283%2F2%29%2Alog%285%2Ca%29=log%285%2Cx%29%29\"
\n" ); document.write( "\"3%2F2=log%285%2Cx%29%2Flog%285%2Ca%29\"
\n" ); document.write( "\"3%2F2=log%285%2C%28x-a%29%29\"
\n" ); document.write( "\"5%5E%283%2F2%29=x-a\"
\n" ); document.write( "\"5%5E%283%2F2%29%2Ba=x\"
\n" ); document.write( "

Algebra.Com's Answer #409229 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
I get different answers depending on how I simplify the expression \"5%5E%283log%2825%2Ca%29%29\"
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\n" ); document.write( "\"5%5E%283log%2825%2Ca%29%29\"
\n" ); document.write( "= \"5%5E%28log%2825%2Ca%5E3%29%29\"
\n" ); document.write( "Since 25 = 5^2:
\n" ); document.write( "= \"5%5E%28log%285%2Ca%5E6%29%29\"
\n" ); document.write( "= \"a%5E6\"
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