document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=655646>Question 655646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> supplement and compliment of (6x-5) degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409224 by </B><A HREF=/tutors/aboutme.mpl?userid=MathDazed><B>MathDazed(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathDazed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathDazed><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The complement of (6x-5) is 90-6x-5 = 85-6x\r<BR>\n" );
document.write( "\n" );
document.write( "The supplement of (6x-5) is 180-6x -5 = 175-6x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );