document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=655587>Question 655587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the principal which would amount to $6900 in 3 years at 5% simple interest per annum?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409219 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I=Prt is the formula for simple interest.  And the formula for the accumulated amount is A = P+I  (the original principal plus the interest accumulated.)<P><BR>\n" );
document.write( "6900-I=x and I = x*.05*3<P><BR>\n" );
document.write( "I = .15x so 6900 - .15x = x<P><BR>\n" );
document.write( "6900 = 1.15x<P><BR>\n" );
document.write( "6900/1.15 = x = 6000 </SPAN>\n" );
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