document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=655637>Question 655637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve 40-2t=10? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409217 by </B><A HREF=/tutors/aboutme.mpl?userid=MathDazed><B>MathDazed(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathDazed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathDazed><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40 - 2t = 10\r<BR>\n" );
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document.write( "Subtract 40 from both sides\r<BR>\n" );
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document.write( "-40 + 40 - 2t = 10 - 40\r<BR>\n" );
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document.write( "-2t = -30\r<BR>\n" );
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document.write( "Divide both sides by -2\r<BR>\n" );
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document.write( "-2t/-2 = -30/-2<BR>\n" );
document.write( "t = 15 </SPAN>\n" );
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