document.write( "Question 655174: The probability that machine A will break down on a particular day is P(A) = 1/50; similarly, for machine B, P(B) = 1/100. Assuming independence, on a particular day,\r
\n" ); document.write( "\n" ); document.write( "a. What is the probability that both will break down?
\n" ); document.write( "b. What is the probability that at most one will break down?
\n" ); document.write( "c. What is the probability that neither will break down?
\n" ); document.write( "d. What is the probability that one or the other will break down?
\n" ); document.write( "e. What is the probability that exactly one will break down?
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Algebra.Com's Answer #409134 by stanbon(75887)\"\" \"About 
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The probability that machine A will break down on a particular day is P(A) = 1/50; similarly, for machine B, P(B) = 1/100. Assuming independence, on a particular day,
\n" ); document.write( "a. What is the probability that both will break down?z::(1/50)(1/100)= 1/5000
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\n" ); document.write( "b. What is the probability that at most one will break down?
\n" ); document.write( "::: 1 - 1/5000 = 4999/5000
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\n" ); document.write( "c. What is the probability that neither will break down?::(49/50)(99/100)
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\n" ); document.write( "d. What is the probability that one or the other will break down?::::
\n" ); document.write( "(1/50)(99/100) + (1/100)(49/50
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\n" ); document.write( "e. What is the probability that exactly one will break down?
\n" ); document.write( "::: 1 - P(none break down) = 1 - (49/50)(99/100)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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