document.write( "Question 655397: the sum of the digits of a two digit number is 10. The number formed by reversing the digits is 4 less than 5 times the original number. Find the original number.
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document.write( "can you explain this one to me thank you so much. \n" );
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Algebra.Com's Answer #409088 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! the sum of the digits of a two digit number is 10. The number formed by reversing the digits is 4 less than 5 times the original number. Find the original number. \n" ); document.write( "can you explain this one to me thank you so much. \n" ); document.write( "** \n" ); document.write( "let u=units digit \n" ); document.write( "let t=tens digit \n" ); document.write( "u+t=10 \n" ); document.write( "t=10-u \n" ); document.write( "original number=10t+u \n" ); document.write( "reversed digit number=10u+t \n" ); document.write( ".. \n" ); document.write( "10u+t=5(10t+u)-4 \n" ); document.write( "10u+t=50t+5u-4 \n" ); document.write( "49t-5u=4 \n" ); document.write( "49(10-u)-5u=4 \n" ); document.write( "490-49u-5u=4 \n" ); document.write( "54u=486 \n" ); document.write( "u=486/54=9 \n" ); document.write( "t=10-u=1 \n" ); document.write( "original number=10t+u=10+9=19 \n" ); document.write( ".. \n" ); document.write( "check: \n" ); document.write( "reversed digit number=10u+t=90+1=91 \n" ); document.write( "5 times the original number=5*19=95 \n" ); document.write( "difference=4 \n" ); document.write( " \n" ); document.write( " |