document.write( "Question 655397: the sum of the digits of a two digit number is 10. The number formed by reversing the digits is 4 less than 5 times the original number. Find the original number.
\n" ); document.write( "can you explain this one to me thank you so much.
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Algebra.Com's Answer #409088 by lwsshak3(11628)\"\" \"About 
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the sum of the digits of a two digit number is 10. The number formed by reversing the digits is 4 less than 5 times the original number. Find the original number.
\n" ); document.write( "can you explain this one to me thank you so much.
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\n" ); document.write( "let u=units digit
\n" ); document.write( "let t=tens digit
\n" ); document.write( "u+t=10
\n" ); document.write( "t=10-u
\n" ); document.write( "original number=10t+u
\n" ); document.write( "reversed digit number=10u+t
\n" ); document.write( "..
\n" ); document.write( "10u+t=5(10t+u)-4
\n" ); document.write( "10u+t=50t+5u-4
\n" ); document.write( "49t-5u=4
\n" ); document.write( "49(10-u)-5u=4
\n" ); document.write( "490-49u-5u=4
\n" ); document.write( "54u=486
\n" ); document.write( "u=486/54=9
\n" ); document.write( "t=10-u=1
\n" ); document.write( "original number=10t+u=10+9=19
\n" ); document.write( "..
\n" ); document.write( "check:
\n" ); document.write( "reversed digit number=10u+t=90+1=91
\n" ); document.write( "5 times the original number=5*19=95
\n" ); document.write( "difference=4
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