document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=655262>Question 655262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> After 12 years I shall be three times as old as I was 4 years ago. Find my present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #409067 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=409067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=your present age<BR>\n" );
document.write( "Four years ago, your age was x-4<BR>\n" );
document.write( "After 12 years, your age will be x+12<BR>\n" );
document.write( "So our equation to solve is:<BR>\n" );
document.write( "x+12=3(x-4)<BR>\n" );
document.write( "x+12=3x-12 add 12 to and subtract x from each side<BR>\n" );
document.write( "12+12=3x-x<BR>\n" );
document.write( "2x=24<BR>\n" );
document.write( "x=12----your present age\r<BR>\n" );
document.write( "\n" );
document.write( "CK<BR>\n" );
document.write( "12+12=3(12-4)<BR>\n" );
document.write( "12+12=36-12<BR>\n" );
document.write( "24=24\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );