document.write( "Question 655232: The length of a rectangle is 9.7cm more than 4 times the width. If the perimeter of the rectangle is 91.4cm what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #409039 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! L=4W+9.7 \n" ); document.write( "P=2L+2W \n" ); document.write( "91.4=2(4W+9.7)+2W \n" ); document.write( "91.4=8W+19.4+2W \n" ); document.write( "91.4=10W+19.4 \n" ); document.write( "10W=91.4-19.4 \n" ); document.write( "10W=72 \n" ); document.write( "W=72/10 \n" ); document.write( "W=7.2 ANS. FOR THE WIDTH. \n" ); document.write( "L=4*7.2+9.7 \n" ); document.write( "L=28+9.7 \n" ); document.write( "L=37.7 ANS FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "91.4=2*37.7+2*8 \n" ); document.write( "91.4=75.4+16 \n" ); document.write( "91.4=91.4 \n" ); document.write( " \n" ); document.write( " |