document.write( "Question 655283: I need help on understanding how to solve this problem using substitution and elimination. Please show me how:
\n" ); document.write( "4x+5y=13
\n" ); document.write( "4x+3y=9
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Algebra.Com's Answer #409027 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Elimination:
\n" ); document.write( "4x+5y=13
\n" ); document.write( "4x+3y=9 | Subtracting 2nd from the 1st EQ to eliminate x
\n" ); document.write( " 2y = 4
\n" ); document.write( " y = 2 and x = 3/4 \"4x+=+-5%2A2+%2B+13\"\r
\n" ); document.write( "\n" ); document.write( "substitution
\n" ); document.write( " 4x+5y=13 0r 4x = -5y +13
\n" ); document.write( " 4x+3y=9 0r 4x = -3y + 9
\n" ); document.write( " -3y +9 = -5y + 13
\n" ); document.write( " 2y = 4
\n" ); document.write( " y = 2 and x = 3/4 \n" ); document.write( "
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