document.write( "Question 655156: Find the slope of a line perpedicular to the line containing the points (-1, -11) and (9, 10) \r
\n" ); document.write( "\n" ); document.write( "Which line would be perpendicular to y = 3x + 2?
\n" ); document.write( "a) 3x-y=-1 b)y-3x=-1 c) x+3y=-1 d) 6x-2y=-1\r
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\n" ); document.write( "\n" ); document.write( "PLEASE HELP ME! \n" ); document.write( "
Algebra.Com's Answer #408960 by nerdybill(7384)\"\" \"About 
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Find the slope of a line perpedicular to the line containing the points (-1, -11) and (9, 10)
\n" ); document.write( "slope between two points:
\n" ); document.write( "(y2-y1)/(x2-x1)
\n" ); document.write( "(10-(-11))/(9-(-1))
\n" ); document.write( "(10+11)/(9+1)
\n" ); document.write( "21/10
\n" ); document.write( "a line perpendicular would be the negative reciprocal:
\n" ); document.write( "-10/21 (answer)
\n" ); document.write( ".
\n" ); document.write( "Which line would be perpendicular to y = 3x + 2?
\n" ); document.write( "a) 3x-y=-1 b)y-3x=-1 c) x+3y=-1 d) 6x-2y=-1
\n" ); document.write( "answer is (c)
\n" ); document.write( "because:
\n" ); document.write( "x+3y=-1
\n" ); document.write( "3y=-x-1
\n" ); document.write( "y=(-1/3)x-(1/3)
\n" ); document.write( "this equation has the negative reciprocal slope of 3 \n" ); document.write( "
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